x^2-3*0,2x+0,2^2=0

Solution for x^2-3*0,2x+0,2^2=0 equation:

x^2-3*0.2x+0.2^2=0

We add all the numbers together, and all the variables

x^2-3*0.2x+0.04=0

Wy multiply elements

x^2+0x+0.04=0

We add all the numbers together, and all the variables

x^2+x+0.04=0

a = 1; b = 1; c = +0.04;
Δ = b2-4ac
Δ = 12-4·1·0.04
Δ = 0.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{0.84}}{2*1}=\frac{-1-\sqrt{0.84}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{0.84}}{2*1}=\frac{-1+\sqrt{0.84}}{2}
$